English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Okay. I have 127.2 grams of C7H5(NO2)3 or 0.5600 mol C7H5(NO2)3 or 3.37x10^23 particles of C7H5(NO2)3. I need to somehow determine the number of N atoms. How could I go about doing so? I assume I need to multiply one of the amounts by a fraction or something but I don't know the formula.

2007-11-07 11:00:12 · 1 answers · asked by Brookeachu. 2 in Science & Mathematics Chemistry

1 answers

You told us that you have 3.37x10^23 "particles" of C7H5(NO2)3. But each "particle" of C7H5(NO2)3 obviously contains 3 N atoms. So this is a simplest arithmetic multiplication to find the total number of N atoms, is not it?
The answer: 3 x 3.37x10^23, assuming 3.37x10^23 is correct # of C7H5(NO2)3 "particles".

2007-11-08 02:48:16 · answer #1 · answered by Hahaha 7 · 0 0

fedest.com, questions and answers