i dont kno the equations for angular momentum
2007-11-07 06:55:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
no idea...... but it will require an extremely powerful force to move something as heavy as that.... wots this question 4?
2007-11-07 07:07:41 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You don't need equations for angular momentum. All you need to know is the rate of rotation of the clock hand, which means you must know which hand you're dealing with.
The linear velocity of the tip of a clock hand is
v = omega*R
where omega = angular velocity and R = radius of circle traced by tip of clock hand
Setting the tip velocity to the speed of light, and the angular velocity to 2*pi radians per minute (corresponding to the second hand of the clock), we get:
c = (2*pi rad/min)*R
(3*10^8 m/s) = (0.1047 rad/s)*R
R = 2,860,000,000 m
The second hand must be 2,860,000,000 meters long for its tip to move at the speed of light (assuming steady movement).
2007-11-07 15:06:58 · answer #2 · answered by lithiumdeuteride 7 · 0⤊ 0⤋
L=mvr is the equation for angular momentum.
2007-11-07 15:00:10 · answer #3 · answered by Kaity 2 · 0⤊ 0⤋
a light second ? not a clue
2007-11-07 15:00:43 · answer #4 · answered by Anonymous · 0⤊ 0⤋