simplify and write the answer only in positive exponents?

0 ⤊

simplify and write the answer only in positive exponents?

(x^2y^-2/z^-2)^-1

2007-11-07 05:29:27 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

(x^2y^2/z^2)^-1
=1/(x^2y^2/z^2)
=(1/x^2y^2)*z^2
=z^2/(x^2y^2)

2007-11-07 05:49:00 · answer #1 · answered by Mac 2 · 0⤊ 0⤋

(x^2*y^-2/z^-2)^-1 = 1/(x^2*y^-2/z^-2) = 1/(x^2*y^-2*z^2) =
(1/(x^2*z^2))/(y^2)= y^2/(x^2*z^2)

The trick is that if a is an expression such that f(x) = a^-n, then f(x) = 1/(a^n)

2007-11-07 13:36:56 · answer #2 · answered by Ricky V 1 · 0⤊ 0⤋

y^2/(z^2x^2)

2007-11-07 13:34:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋

x^2/(y^2z^2)

2007-11-07 13:32:58 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋