The crystal structure of an ionic compound consists of alternating cations and anions lying next to each other in three dimensions. If the cation radius is 55.9% of the anion radius and the distance between the cation nuclei is 580. pm, what are the radii of the two ions? (Note: This ionic compound is a three dimensional array. The cation to cation, center-to-center distance specified is through the center of the anion.)
anion
cation
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2007-11-07 05:25:00 · 1 answers · asked by jnester0289 1 in Science & Mathematics ➔ Chemistry
Let one radius be called r. Then the second radius is 580pm - r. Because one radius is 55.9% (0.559) of the other:
580 - r = 0.559r
580 = 1.559r
r = 372 pm (the first radius)
580pm - 372pm = 208 pm (the second radius)
2007-11-07 06:05:24 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋