x squared+x-20=?

Answer 1

x^2 + x - 20
(x - 5) (x + 4)

x - 5 = 0
x = 5

x + 4 = 0
x = -4

Solution set : (5. -4)

Answer 2

since that is a simple trinomial and not a perfect square trinomial
the standard equation is x^2 + bx +C...
where B= 1 and C= -20 since your equation is X^2+x-20
next step
Find the number that would satisfy the following
U *V = C
U + V = B
where U and v are real numbers
by trial and error we will arrive at
-4 and 5
because it satisfies the following
(-4) * (5) = -20
-4 + 5 = 1
thus the factor of the trinomial X^2 + X + 20 =

(x-4) * (x+5)

since x is a variable..... the value of the trinomial depends upon the value you substitute with the variable X

so assuming that x=1
then the value of the trinomial will become
1^2 +1 -20..
= 2-20...
= - 18

Answer 3

x^2 + x - 20 =(x + 5) (x - 4)

Answer 4

Which factors of -20, add up to +1?
-20 = (-4)(5)
&
5 - 4 = 1
So, the expression factors as follows:
(x + 5)(x - 4)

Use FOIL to check.

Answer 5

x^2+x-20

(x+5)(x-4)

x=-5 or 4

Answer 6

x^2 + x - 20 = 0
(x - 4) (x + 5) = 0
then x1 = 4 and x2 = -5

Answer 7

(x + 5)(x - 4) = ?

the ? usually represents an unknown y that varies with x.
in this case we can say that when y = 0 the curve cuts the x axis at x = -5 and 4.

you could also differentiate the fist equation x^2 + x - 20 to find the stationary points...

dy/dx = 2x + 1
when dy/dx = 0; x = -0.5

i could go on... but im boring myself

Answer 8

(x+5)(x-4)

Answer 9

x^2 + x - 20 = 0
(x + 5)(x - 4) = 0

x + 5 = 0, x = - 5
x - 4 = 0, x = 4

Answer: x is either - 5 or 4

Answer 10

The answer could take virtually any value, depending on the value of x.