The question has 6 different parts but please help...we haven't even covered this yet!
1) A ball of mass 20.0 g is launched horizontally from a height of 2.20 m. It is observed to travel 3.15 m horizontally. What was the initial speed of the ball?
2) What is the initial momentum of the ball?
3) What is the initial kinetic energy of the ball?
4) If the ball is instead launched at a pendulum of mass 144.0 g and makes a perfectly inelastic collision, how fast is the pendulum+ball going immediately after the collision?
5) What is the kinetic energy of the pendulum+ball immediately after the collision?
6) What is the maximum height obtained by the pendulum+ball?
2007-11-07 01:08:08 · 2 answers · asked by hmm 1 in Science & Mathematics ➔ Physics
1.Time in the air
t=sqrt(2h/g)
Vh=S/t
V=Vh since it was launched horizontally.
2. P=mV
3. Ke=0.5 mV^2
4. m1u1=m1V1 + m2V2
5. Ke(ball)= 0.5m1V1^2
Ke(pendulum)= 0.5m2V2^2 and
Ke(ball before collision)=Ke(ball after collision) + Ke(pendulum after collision).
6 what? You mean the pendulum
pe=ke
mgh = 0.5mV^2
h= V^2 / (2g)
2007-11-07 01:44:27 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
they're the two with the aid of gauge invariances. Momentum is with the aid of spatial gauge invariance and capability with the aid of temporal gauge invariance. blended they're with the aid of invariance of the regulations of physics under spacetime translation.
2016-12-08 14:40:28 · answer #2 · answered by ? 4 · 0⤊ 0⤋