Can I prepare 100ml of 3M sodium acetate solution by mixing 24.61g of sodium acetate anhydrous into distilled water then topped up to 100ml?
2007-11-06 19:35:59 · 3 answers · asked by pUn|sh3r 2 in Science & Mathematics ➔ Chemistry
Yes you could. the RMM of sodium acetate anhydrous is 82.03 g/mol so your 24.61 grams is 24.61/82.03 = 0.3 moles.
0.3 moles/ 100 ml = 3 moles /litre
The solubility of sodium acetate anhydrous is 54g/100g water so that wouldn't be an issue.
2007-11-06 20:54:50 · answer #1 · answered by CJ 3 · 0⤊ 0⤋
Yes but remember to do it in a volumetric flask and to wash out you weighing vessel into the flask too!
2007-11-07 09:38:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋
THE EQUATION
24.61g / 82.03 g/mol (anhydrous) =0.3 mol
0.3 mol / 0.1 lit = 3 mol/lit =3M
2007-11-07 05:12:35 · answer #3 · answered by mazumah 2 · 0⤊ 0⤋