orgo has let out 50 meters of kite string when he observes that his kite is directly above zorna.?

Question

If Orgo is 35 meters from Zorna,how high is the kite?

Plz help i dont get it

Answer 1

Draw the triangle. Assume that the kite string is the right triangle hypotenuse, and 35m is distance along assumed flat ground. Solve for other leg of triangle:

height = sqrt (50^2 - 35^2)
= 5*sqrt (10^2 - 7^2)
= 5*sqrt(51) m

Answer 2

It is a right triangle problem. Since the kite is right over Zorna, the angle between the kite, him, and Orgo is 90 degrees. So one of the two arms is 35 meters, and the base is 50 meters. The height is the other arm.

So

a^2 + b^2 = c^2

a^2 + (35)^2 = (50)^2

a^2 + 1225 = 2500

a^2 = 2500-1225 = 1275

therefore

a = sqrt(1275)

a=35.707142

Normally though, these questions work it so that the number turns out to be an integer.

Answer 3

Draw a triangle, with orgo, zorna and the kite at the three corners.

The base (horizontal side) of the triangle is the distance between orgo and zorna. Label that "35 m".

The diagonal side is the distance between orgo and his kite. That is "50 m".

The final side (from zorna straight up to the kite) is what you want to find out. Label that "h" for height.

Notice that this is a right triangle, because one side is vertical and one side is horizontal.

That means you can use the pythagorean theorem:

(35m)² + h² = (50m)²

Solve that for "h".