differential equation?

Question

Find a fundamental set of solution for the differential equation

2y''-10y'+6y=0

determine the general solution
and find the solution of the equation with the initial condiction y(-square root 3)=0 and y'(-square root of 3)=0

Answer 1

Obviously, start by rewriting it is y"-5y'+3y = 0

The look at e^(rx) and e^(sx), where r and s are the two roots of the quadratic equation x^2-5x+3. I think you'll find they solve the differential equation. :)