the problem is to (create a cross between 2 heterozygous turtle shurbs include the punnett square and include a phenotypic ratio) TtYyRrBb
2007-11-06 14:36:10 · 2 answers · asked by the student 2 in Science & Mathematics ➔ Biology
This is worse than a trihybrid cross which would have three pairs of alleles ... your problem has four pairs of alleles.
The Punnett square you need if you are going to show all the possibilities among the offspring will be 16 x 16. Across the top you will have 16 gametes. Down the side you will have the same 16 gametes since the parents are the same genotype. The 16 gametes are:
TYRB
TYRb
TYrB
TYrb
TyRB
TyRb
TyrB
Tyrb
tYrB
tYrb
tYRB
tYRb
tYrB
tYrb
tyRB
tyRb
tYrB
tYrb
tyrB
tyrb
Good luck working this out. Be sure to make the Punnett square wide enough to fit all the letters in each box.
2007-11-06 14:52:42 · answer #1 · answered by ecolink 7 · 0⤊ 0⤋
its gonna be an 8x8, not a 16x16
2007-11-07 23:35:13 · answer #2 · answered by Lauren C 1 · 0⤊ 1⤋