please help me im not sure if i got the answer to this math right?

Question

WHEN SCHOOL ENDS AT 2:30 P.M., JACOB STARTS TO WALK HOME AT A RATE OF 3.0 MILES PER HOUR.IF HIS BROTHER LEAVES SCHOOL 5 MINUTES LATER AND WALKS AT A RATE OF 3.6 MILES PER HOUR, AT WHAT TIME WILL HE CATCH UP TO JACOB? SHOW ALL WORK PLEASE

Answer 1

3 miles per hour = 0.05 miles per minute.
3.6 miles per hour = 0.06 miles per minute.
For every 1 minute, distance between them will be subtracted to 0.01 miles.
After the first 5 minutes, distance between them is 0.05 * 5 = 0.25 miles.
So, in 0.25/0.01 min = 25 min, Jacob's brother will catch up Jacob, or at 2:30 PM + 5 min + 25 min = 3:00 PM

Answer 2

First figure how far Jacob walks before his brother starts by the following; 3 miles / 1 hour x 5 /60 hour = 15 / 60 miles = .25 miles. Jacob`s brother`s relative speed with respect to Jacob`s speed is 3.6 mph -3.0 mph = .6 mph . Now calculate how long it will take for his brother to gain ..25miles at .6 mph as follows: .25 miles / [ .6 miles / 1 hour] = .4167 hours. .4167 hours x 60 minutes / 1 hour = 25 minutes. Now add this to the five minutes that Jacob had walked before his brother started. 5minutes + 25 minutes = 30 minutes. Now add this to the starting time of 2:30 p m. 2:30 pm + 30 = 3:00 pm. This is the time that Jacob`s brother will catch up with him. Jacob will have walked for 1/2 hour at 3.0 miles/ 1 hour. This amounts to 1/2 hour x 3 miles/ 1hour =1 1/2 miles. His brother will have walked 25 / 60 hour at 3.6 miles / 1 hour. This amounts to 25 / 60 hour x 3.6 miles/ 1 hour = 1 1/2 miles. The brothers will be walking side by side at a point 1 1/2 miles closer to home at 3:00 P. M..