The element Palladium (Pd) has the electron configuration 4d^10 5s^0. Why does this element have the S orbital noted if it is empty?
2007-11-06 13:56:47 · 4 answers · asked by rexhenry11 2 in Science & Mathematics ➔ Chemistry
It's been a while since I've take a chem class, but I don't think that is a necessity. It's just standard to write it like that.
2007-11-06 13:59:15 · answer #1 · answered by Me 5 · 0⤊ 0⤋
Many of the elements before Palladium in the table have a full 5s orbital. As the 4d electrons near 10, the energy situation will favor that the electrons are moved "down" to the 4d level rather than remaining in the 5s level.
2007-11-06 22:00:47 · answer #2 · answered by cattbarf 7 · 1⤊ 0⤋
when the electrons accumulate the 4d becomes less energetic than the 5s and the electrons fill the 4d in this case. It is just an exception to the rules. It is one of many you will come across.
2007-11-06 22:04:28 · answer #3 · answered by kentchemistry.com 7 · 0⤊ 0⤋
perhaps to note which isotope you are working with because generally Pd has about six common isoptopes with the most stable being 107Pd... which would have an e configuration of 4d^105s^1
2007-11-06 22:04:26 · answer #4 · answered by Anonymous · 0⤊ 0⤋