There's 3 parts to the question:
a. What is the momentum of an 8-kg bowling ball rolling at 2 m/s? (momentum = mass x velocity)
b. If the bowling ball rolls into a pillow and stops in 0.5 s, calculate the average force it exerts on the pillow.
c. What average force does the pillow exert on the ball?
2007-11-06 13:19:14 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
(a) Momentum = Mass x Velocity = 8 x 2 = 16 Kgm
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(b) Rate of change of momentum = (mv - mu)/t
-------------------"--------------------= 16/.5 = 32 N
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(c) Equal & opposite force will be exerted by the pillow=32N
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2007-11-06 14:23:07 · answer #1 · answered by Joymash 6 · 3⤊ 0⤋
a) OK p=mv= 16 kg m / s
b) F(avg) momentum x time
c) It returns the favor with F(reaction) = F(avg)
2007-11-06 13:42:25 · answer #2 · answered by Edward 7 · 0⤊ 1⤋
None of these answers help me. Can someone explain it in words that I can understand in?
2014-12-11 12:45:30 · answer #3 · answered by Dulce 1 · 0⤊ 1⤋