Is there even enough in formation to solve this trig. story problem, I need answer + steps please?

Question

Solve the problem. Round answers to the nearest tenth if necessary.

Two quadrilaterals (four-sided figures) are similar. The lengths of the three longest sides of the first quadrilateral are 60 ft, 40 ft, and 30 ft. The lengths of the two shortest sides of the second quadrilateral are 6 ft and 3 ft. Find the unknown lengths of the sides of these two figures.

Answer 1

Yes. The 30 ft side of the larger figure corresponds to the 6 ft side of the smaller figure. From the information we have about the smaller figure we know the shortest side is half the second shortest side. So the shortest side of the larger figure is half of 30 or 15.
From the information we have about the larger figure, we know the longest side is twice the second shortest side. so the longest side of the smaller figure is twice the 6ft, or 12 ft. Also from the larger figure we know the second longest side is four thirds of the second shortest side. So the second longest side of the smaller figure is 4/3 times 6, or 8ft.
For the larger we have:
60ft, 40ft, 30ft, 15ft
For the smaller figure we have:
12ft, 8ft, 6ft, 3ft