0.15 M CaCl2
and
0.26 M Al(NO3)3.
Since the question is askingfor "all ions" am I to assume that I must multiply the molar amounts by avogadro's #?
2007-11-06 11:49:18 · 2 answers · asked by BugGurl 3 in Science & Mathematics ➔ Chemistry
No, the question just asks for concentrations. When a strong electrolyte dissolves, it dissociates completely into the component ions. So, one formula unit of CaCl2 forms 1 Ca2+ ion and 2 Cl- ions. So, in this solution, the concentration of Calcium ions will be 0.15 M, and the concentration of chloride ions will be 0.30 M.
Can you do the next one?
2007-11-06 11:57:22 · answer #1 · answered by hcbiochem 7 · 4⤊ 0⤋
No - your question asks for conc. not no. of molecules.
0.15 M CaCl2 gives [Ca++] = 0.15M, [Cl-] = 0.30M
0.26M Al(NO3)3 gives [Al+++] = 0.26M, [NO3] = 0.78M
2007-11-06 11:59:45 · answer #2 · answered by Aurium 6 · 4⤊ 0⤋