A student determines the mass of a rock to be 196 grams, but the actual mass of the rock is 200 grams. The student's approximate percent deviation (percentage of error) is:
2007-11-06 10:18:29 · 4 answers · asked by musichick243 2 in Science & Mathematics ➔ Mathematics
The student measures the mass to be 196 but the actual mass is 200.
This means that the student is out by (200-196) = 4g
The percentage is 100 * 4 / 200 = 400 / 200 = 2. So the error is 2%
2007-11-06 10:23:05 · answer #1 · answered by davidbgreensmith 4 · 0⤊ 0⤋
You get the percentage error by dividing how much they were wrong by the total true amount. So it's (200-196) / 200 = 4/200 or 2/100 or 2%.
2007-11-06 18:24:28 · answer #2 · answered by ansrdog 4 · 0⤊ 0⤋
Hello,
200 - 196 = 4 now 4/200 = 2%.
Hope This Helps!
2007-11-06 18:22:43 · answer #3 · answered by CipherMan 5 · 0⤊ 0⤋
(196/200) x 100 = 98
100-98=2
so 2%
2007-11-06 18:25:52 · answer #4 · answered by Megan 2 · 0⤊ 0⤋