chem and math problem help!!?

Question

How many kilojoules of energy woulb bee needed to fill a swimming pool with the dimensions 12 ft x 3 ft x 8 ft if you want the temp to increase from 26C to 30C Steps included!!

Answer 1

First, convert the pool measurements to metric:

12 ft = 12 ft * 30.48 cm/ft = 365.76 cm
Similarly, 3 ft = 91.44 cm and 8 ft = 243.84 cm

So the volume of the pool is 365.76*91.44*243.84 = 8.155 * 10^6 cm³

If we take the density of water as 0.998 g/cm³, the mass of water in the pool is
8.155 * 10^6 cm³ * 0.998 g/cm³ = 8.139*10^6 g

Taking the specific heat of water as 4.184 J/(g-C°), the number of joules of heat required is

8.139*10^6 g * 4.184 J/(g-C°) * 4C° = 1.362*10^8 Joules

Since 1 kilojoule = 1000 joules, the energy required is

1.362*10^8 J * 1KJ/1000J = 1.362*10^5 KJ