A ferrari accelerates from 0 to 100 km/h in 4.8 sec. What force (in newtons) does a passenger?

Question

A ferrari accelerates from 0 to 100 km/h in 4.8 sec. What force (in newtons) does a passenger of mass 68 kg experience during acceleration?

Answer 1

Convert km/hr to m/s

1 kilometer / hr = 0.277777778 meters / second

Next, compute the average acceleration
100*0.28=a*4.8
a=2.8/4.8

F=m*a
so
F=68*2.8/4.8
=39.7 N

j

Answer 2

understanding that velocity = Distance / time D= ? Time = 4.80 sec ( one hundred.0 km * 1hour *1000 m) ----------------------------------------... = 27.80 m/s = V ( hour *3600 sec *one million km) So 27.80 m/s = D/4.80 sec D= 27.80 m/s * 4.80 s = 133.3 meter --------------- the seconds cancel-out utilizing X(very final)= X(preliminary) + V(preliminary) * t + one million/2 a* t^2 133.3 meter = 0 + 0 + one million/2 *a*(4.80^2) 133.33 meter = 11.fifty two s^2 *a ** a = 133.33 m / 11.fifty two s^2 = 11.6 m/s^2 utilizing Newtons regulation F= m*a ** neglecting the weigh of the motor vehicle F=(sixty 8.0 kg * 11.6 m/s^2) = 787.02 Kg*m/s^2 or Newtons P.s: it extremely is the attitude of a individual outdoors the motor vehicle, if it replace into interior at a persevering with velocity the acceleration could be 0.