Does anyone know how to find an equation for lines? Help Please?!?

Question

Given the slope of the line and a point on the line, find an equation for each line.
- A line of slope 4 passing through the point (0,2)

I remember rise over run and y=mx+b but how do I apply that to this question?

Answer 1

Using y = mx + b
'm' is the slope (4)

y = 4x + b

The point is (0,2)
substitute these numbers in for 'x' & 'y'

2 = 4(0) + b
2 = 0 + b
b = 2

So equation is y = 4x + 2

Answer 2

easy! first, you need to know what the parts in the equation y=mx+b mean. the m part is the slope, so since the slope of the equation is 4, you just plug it in. so now you have: y= 4x +b. now, the b is the y intercept. the y intercept is the point you see that is on the y axis (the vertical line on a coordinate graph). you are given that the line passes thru the point (0,2). this point is the y intercept. how do you know? well, when you look at a coordinate point, the first number is the point for the x axis and the second is for the y axis. so this point (0, 2) has to be on the y axis, because the x point is 0. so, just plug in the y point for b.
in the end, your equation will be.....
y= 4x + 2

hope this helps!

Answer 3

y=mx+b like you said. m is the slope (rise over run), so you can put that in to get y=4x+b. You have a point on the line (0,2), which you can use to solve for b -> 2=4*(0) + b. Now you know what b is, so you get y=4x+2

Answer 4

2 would be the y intercept b/c that is where it crosses the y axis
so then you have
y=4/1x+2