2007-11-06 08:44:05 · 8 answers · asked by lisa j 1 in Science & Mathematics ➔ Chemistry
Here, copper(II) sulfate (CuSO4) is added to barium chloride (BaCl2). The result is a pale blue solution and white precipitate. The blue color is due to Cu2+(aq).
CuSO4 + BaCl2 --------> BaSO4 + CuCl2;
White precipitate is of Barium Sulphate .
2007-11-06 19:16:27 · answer #1 · answered by sb 7 · 0⤊ 0⤋
This Site Might Help You.
RE:
what is the molecular reaction equation for Copper(II)sulfate + barium chloride?
2015-08-18 21:01:50 · answer #2 · answered by Gigi 1 · 0⤊ 0⤋
Yes BaCl + NaPO4 ----> BaPO4 + NaCl (No coefficients needed to balance. It's already balanced.) For the other one, a reaction would occur, but you'd just be creating the same products as reactants: NaCl + NaPO4 ----> NaPO4 + NaCl (Again, it's already balanced.)
2016-03-18 05:36:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋
CuSO4 + BaCl2 ===> BaSO4(s) + CuCl2
2007-11-06 09:05:25 · answer #4 · answered by shyam_2sharma5 1 · 0⤊ 0⤋
CuSO4 + BaCl2 ===> BaSO4(s) + CuCl2
2007-11-06 08:50:00 · answer #5 · answered by steve_geo1 7 · 0⤊ 0⤋
CuSO4(4 as a sub script) + BaCl2(as a sub script)=CuCl2(2 as a sub script)+ BaSO4(4 as a sub script)
2007-11-06 08:51:38 · answer #6 · answered by lily 3 · 0⤊ 0⤋
CuSO4 + BaCl2------------>BaSO4+ CuCl2
dis is a double displacement reaction.
2007-11-06 23:29:13 · answer #7 · answered by andromeda 2 · 0⤊ 0⤋
cuso4+bacl=cucl2+baso4
2007-11-06 23:56:05 · answer #8 · answered by chilly 2 · 0⤊ 0⤋