even more physics?

Question

two window washers, bob and joe, are on a 3m long, 395N scaffold supported bt two cables attached to its ends. bob weighs 800N and stands 1m from the left end. two meters from the left end is 500 N washer equipment. joe is .5m from the right end and weighs 990N. given that the scaffold is in rotational and transitional equilibrium, what are the forces on each cable

Answer 1

Summation of vertical forces
T1 + T2= W1+ W2 + W3 + W4=2685N
where
W1 - weight of Bob
W2 - washer equipment
W3 - weight of Joeb
W4 - scaffold

Moment about the left side where T1 reacts
M(left end)= L T2 - R1W1 - R2W2 - R3W3
T2=(R1W1 + R2W2 + R3W3 + R4W4)/L
T2=(1x800 + 2x 500 +2.5 x 990 +1.5x395)/3=
T2=1622.5 N

substituting into the first equation
T1 + (R1W1 + R2W2 + R3W3)/L=W1+ W2 + W3
T1=W1+ W2 + W3 + W4- (R1W1 + R2W2 + R3W3 +R4W4)/L=
T1= 2685N - 1622.5 N=1062.5N

Answer 2

depends on how much water is in the buckets to wash windows