It is asking what numbers are 7 units away from 0 when you subtract 3 from them.
|10-3| = 7
|-4 - 3| = |-7| = 7
So 10 and -4, when you subtract 3 from them, are both 7 units away from 0. One in the positive direction and one in the negative direction.
2007-11-06 08:24:51
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answer #1
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answered by Jeƒƒ Lebowski 6
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the answer is {x| -4, 10}
the lines | ... | mean absolute value. Which means whatever is inside the bars is made positive. Example | -3 | = 3, | 4-6 | = 2, | 6-4| = also 2
Now for two different values |X-3| = 7 so we know that -4 - 3 = -7 so |-4 -3| = 7
Narrowing us down to options 1 or 2
also 10 - 3 = 7 so |10 - 3| = 7
basically do the math inside the | ... | first, then make it positive.
2007-11-06 16:26:21
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answer #2
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answered by Carl S 6
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when you solve absolute values - think that what is in the absolute value you take as positive and negative ...so you end up with 2 equations that you solve.
Ix-3I = 7
Equation 1:
+(x-3) = 7
x-3=7
x=7+3
x=10
Equation 2:
-(x-3) = 7
-x+3 = 7
-x=7-3
-x=4
x= - 4
So your solution is -4, 10 (answer b)
The way the solution is written is from the smallest to the largest so naturally -4 is smaller than 10. If you look at all the other options, they are not correct, but they do follow the same patters - smaller number, larger number.
2007-11-06 16:35:27
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answer #3
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answered by slunickosd 4
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it would be the second answer {x -4, 10}, because the the lines on either side of x-3 is the modulus sign, meaning no matter what is inside the modulus sign, the number inside would be a positive number.. and therefore the only answer to satisfy that is the second answer: when x=-4, the answer would be -7, but with the modulus sign the minus disappear, so it would be 7. and when x=10, thats just easy.. 10-3=7!!
2007-11-06 16:27:07
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answer #4
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answered by Anonymous
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The absolute value of (x -3) is 7
so if (x -3) is +ve number
then x -3 = 7
or x = 7 + 3 =10
if (x -3) is -ve number
then x - 3 = -7
x = -7 + 3 = -4
so the answer is {x| -4, 10}
2007-11-06 16:33:11
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answer #5
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answered by ib 4
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Lets flow the absolute value signs over to the right as a plus or minus. So now we know that x-3=+/-7
Solve for x-3=+7
Solve for x-3=-7
for the first we get that x must be 10, for the second we get that x must be -4, so we end up with the data set {x|-4,10}
2007-11-06 16:27:03
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answer #6
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answered by billyjoebob1992 1
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|x - 3| = 7
This is the same as:
-7 = x-3 = 7
Add 3 to all terms getting
-4 = x = 10
S0 answer is {x| -4, 10}
2007-11-06 16:25:40
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answer #7
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answered by ironduke8159 7
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just plug in for each one and see if it gives you 7
rememeber if you plug in the absolute value and it gives you the answer -7..it would still work because the absolute value turns the number positive
ps. the answer is {x|-4, 10}
check to know how to do it
2007-11-06 16:24:56
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answer #8
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answered by Viv 3
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The answer is {xl -4,10}
negative four minus 3 is negative seven, so since it's looking for the absolute value, it turns to positive seven.
ten minus 3 is seven, and it stays as seven because all absolute values are positive.
2007-11-06 16:25:49
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answer #9
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answered by wolfsbane18 2
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|x - 3| = 7
If |x| = 5, then x = either -5 or +5, for example
|x - 3| = 7
Solve both cases
x - 3 = 7
x = 10
x - 3 = -7
x = -4
2007-11-06 16:25:36
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answer #10
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answered by kindricko 7
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