Does bubble in water form converging or diverging lense?

Answer 1

Diverging. Think about what happens when light travels from a substance with a higher index of refraction to one with a lower index.

Answer 2

be conscious that lim (x ? ?) (a million/ [x^5 * {exp(a million/x) – a million} ])/(a million/x^4) = lim (x ? ?) a million/[x (a million/x +a million/2x² + a million/6x³......)] = lim (x ? ?) a million/[a million + a million/2x + a million/6x²...] = a million > 0. on account that, for each a > 0, ? (0, ? ) dx/x4 = a million/3a³ converges, it follows from the decrease comparisson try that ? (a, ?) dx / [x^5 * {exp(a million/x) – a million} ] converges for each a > 0. additionally, ? (0, a ) dx / [x^5 * {exp(a million/x) – a million} ] = ? (a million/a, ?) t^5/( exp(t) -a million) (-a million/t²) dt = ? (a million/a, ?) -t³/( exp(t) -a million) dt. all of us understand that ? (a million/a, ?) t³/exp(t) dt converges. on account that [t³/exp(t)]/[ t³/( exp(t) -a million)] ? a million as t ? ?, the decrease comparisson try exhibits that ? (a million/a, ?) -t³/( exp(t) -a million) dt converges, so as that ? (0, a ) dx / [x^5 * {exp(a million/x) – a million} ] converges. subsequently, this vital could be chop up into the sum of two convergent integrals, meaning it converges.

Answer 3

Diverging lense.