x squared=3+2x?

Answer 1

x² - 2x - 3 = 0
(x - 3)(x + 2) = 0
x =3 , x = - 2

Answer 2

The previous answer is partially correct, here is how you get it the real answer:

x^2 = 3 + 2x

Move everything to one side by subtracting (3 +2x) from both sides:

x^2 -(3 + 2x) = 3 + 2x -(3 +2x)

or

x^2 -3 -2x = 0

or

x^2 -2x -3 = 0

Then factor:

(x - 3)(x + 1) = 0

So x=3 or x= -1

Answer 3

x^2 = 3 + 2x

x^2 -2x -3 = 0

(x -3)(x +1) = 0

=> x -3 = 0 => x = 3
=> x +1 = 0 => x = -1

Answer : x1 = 3 and x2 = -1

Verification

x1 = 3 => 3^2 = 3 + 2(3) => 9 = 9
x2 = -1=> (-1)^2 = 3 + 2(-1) => 1 = 1

Answer 4

since you have x^2 , you know that this is a quadratric equation. So we want to set this equal to 0. So let's subtract 3 and 2x from both sides and we'll have:

x^2 - 2x - 3 = 0

Now we can factor:

(x-3)(x+1) = 0

Now we set each factor to 0 and solve:

x-3 = 0, x + 1 =0

x = 3 and x = -1

Hope that helps!!

Answer 5

x^2-2x-3=0
solve for x
(x-3)(x+1)
x=3, -1

Answer 6

x^2-2x-3=0
solve for x
(x-3)(x+1)
x=3, -1

Answer 7

x^2-2x-3=0
3 is the result of two numbers the difference between them =2
and 3=3*1 and 3-1=2 so
(x-3)(x+1)=0
x-3=0 & x+1=0
x=3 & x=-1

Answer 8

xsquare = 3 + 2x
x = 3 + 2 x / x
cancel out x
so its x = 3+2 = 5
x= 5
x square = 25

Answer 9

x^2=3+2x

x^2-2x-3=0

x^2-3x+x-3=0

(x-3)*(x+1)=0

hence,

x=3 or x= -1

Answer 10

3 3squared= 9 3+ 2(3)= 9