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What is the minimum value of (in terms of ) such that the car moves around the loop without falling off at the top (point )?

If the car starts at height = 63.0 and the radius is = 21.0 , compute the speed of the passengers when the car is at point , which is at the end of a horizontal diameter.
Take the free fall acceleration to be = 9.80 .

If the car starts at height = 63.0 and the radius is = 21.0 , compute the radial acceleration of the passengers when the car is at point , which is at the end of a horizontal diameter.
Take the free fall acceleration to be = 9.80 .

If the car starts at height = 63.0 and the radius is = 21.0 , compute the tangential acceleration of the passengers when the car is at point , which is at the end of a horizontal diameter.
Take the free fall acceleration to be = 9.80 .

2007-11-06 07:17:55 · 1 answers · asked by elturi2k@sbcglobal.net 1 in Science & Mathematics Physics

1 answers

At the top of the loop the centripital acceleration a must me equal or larger then the acceleration due to gravity g.

a= v^2/R so
g<=a=a= v^2/R
v>=sqrt(gR)

Pe(top) - Pe(top of the loop)=Ke
mgh - 2mgR=0.5mV^2
V=sqrt( 2g(h-2R))
Note that if 2(h-2R)
What is horizontal diameter?

2007-11-06 07:49:36 · answer #1 · answered by Edward 7 · 0 6

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