physics merry-go-round problem...help...?

Question

A 50 kg kid stands at the rim of a merry-go-round of radius 2.0 m, rotating with an angular speed of 3.00 rad/s.
1) what is the kid's centripetal accel?
2) what is the minimum force between his feet and the floor of the carousel that is required to keep him in the circular path?
3) what minimum coefficient of static friction is required? will the kid stay on the merry-go-round?

Answer 1

The acceleration is
a=w^2*R

1) a=2*9=18 m/s^2

2) The force is
18*50=900 N

3) The frictional force is
50*9.81*u
with a u of one the force is only 491 N, not enough to hold against the 900 N centripetal force.

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