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A dentist's drill starts from rest. after 3.2 seconds of constant angular acceleration, it turns at a rate of 2.51 * 10^4 rev/min.

1) find the drill's angular acceleration.
2) determine the angle (in radians) through which the drill rotates during this period.

2007-11-06 06:43:27 · 1 answers · asked by Captain Whiskerboy Litterbox 3 in Science & Mathematics Physics

1 answers

first, convert the angular speed to rad/sec

25100*0.1047
2628 rad/sec

using
w=alpha*t
2628=alpha*3.2
alpha=821 rad/s^2

knowing w, compute th
th=.5*alpha*t^2
th=.5*821*3.2^2
th=4204 rad

j

2007-11-06 08:54:13 · answer #1 · answered by odu83 7 · 0 0

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