Okay, I am checking into a hotel for corporate training. We will be assigned roomates. Your roomate will be determined by when you check in. For example:
Male 1 is Male 2's roomate
Male 3 is Male 4's roomate
Female 1 is Female 2's Roomate
Male 33 is Male 34's roomate... and so on.
Is is true that:
a) There is a 50% chance that there will be an odd number of people and a 50% chance that there will be an even number of people?
b)If there is an odd number of people and the rooms definitely only accomodate 2 people, that there will be someone rooming by themself?
and most importantly
c) if I make sure that I check in AFTER everyone else, that assuming a and b are true, there is a 50 % chance that I get my own room (as long as I am the LAST person to check in)
2007-11-06 06:22:34 · 14 answers · asked by rickpetralia 1 in Science & Mathematics ➔ Mathematics
I follow this logic quite well...makes sense to mean...I see no flaws.
2007-11-06 06:25:20 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You are right, but there is a 50% chance of odd number of males, and 50% chance of odd number of females. If there are an odd number of people, and the odd one is a female, then the last female will get a room alone.
The drawback is, how do you know you are the last one? You would have to know how many are going to be there, that there are an odd number of your gender, and that everyone ELSE of your gender had already checked in.
2007-11-06 14:29:26 · answer #2 · answered by Anonymous · 0⤊ 0⤋
yes your logic is false.
there may be 50 % of odd even mix so lets take odd number.
ther is an even nuber of your sex and odd of the other.
therefore 100% chance if last to book of sharing
2007-11-06 14:31:21 · answer #3 · answered by hawaiis0 3 · 0⤊ 0⤋
the probability of odd number of people checking in, is true in theory
what you are saying is like predicting head or tail in a coin toss
2007-11-06 14:31:38 · answer #4 · answered by foe_hammer1 1 · 0⤊ 0⤋
no... you need to create a rule where no male and female can room together for it to work
2007-11-06 15:46:44 · answer #5 · answered by enrique7718 5 · 0⤊ 0⤋
I don't see any flaws but check the other answers first - I'm not that good! =D Good luck =D
2007-11-06 14:26:40 · answer #6 · answered by Alex 4 · 0⤊ 0⤋
sounds right to me, but what if someone else gets the same idea?
2007-11-06 14:31:27 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Ive always hated math, think u could tutor me?!
2007-11-06 14:26:56 · answer #8 · answered by cleo s 3 · 0⤊ 0⤋
That makes sense. I think you're right.
2007-11-06 14:26:18 · answer #9 · answered by Eldridge 3 · 0⤊ 0⤋
Sound right
2007-11-06 14:25:16 · answer #10 · answered by Pascal 4 · 0⤊ 0⤋