thermochemistry question?

Question

i need to figure out the specific heat of a metal
through this given information

metal mass: 27.24 g
dH20: .9973 g/mL
v(h20): ?
Ti (H2O): 23.8 C
Tf(H2O): 31.05 C
change T: 7.25 C
Ti(metal): 100.5 C
Tf(metal): 31.05C
change T(metal): -69.45 C
SH (H2O): 4.184 Jg^-1C^-1
SH(metal): ?

heat of neuatralization

Ti:26.2C
Tf: 35.51C
change T: 9.31
qrxn: ?
no. moles: ?
change Hneut: ?

if you could explain some of that that woudl be great thanks

Answer 1

Please understand that the principle of energy conservation implies that the heat released by the metal is completely absorbed by water. If we let the specific heat of a metal be X (J/g•C), we have:
(27.24 g)*(X J/g•C)*(69.45 C) = [v(H2O)mL]*(.9973 g/mL)*(4.184 J/g•C)*(7.25 C)
Cancel all the unit and rearrange, we have:
X = v(H2O)*0.9973*4.184*7.25 / (27.24*69.45)
Put in the volume of H2O and do the math--you will get the required X: the specific heat of this metal.