hi, help- with differentiation?

Question

can someone take me through the steps of solving dy/dx of the equation y=4/x^2+X√x.
Thankyou.

Answer 1

You mean y = 4/x^2 + x √x, right?

If that's the case, y = 4 x^(-2) + x x^(1/2) = 4 x^(-2) + x^(3/2). Hence,

dy/dx = 4 *(-2) * x^(--2 -1) + 3/2 * x(3/2 -1)
dy/dx = -8 x^(-3) +3/2 x^(1/2) = -8/(x^3) + 3/2√x