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2007-11-06 02:39:25 · 3 answers · asked by Ashley 2 in Science & Mathematics Chemistry

3 answers

Yes.

Nitrogen can form up to 4 bonds (which gives it 8 valence shell electrons). However, when it does form two double bonds, it will have a positive charge.

Remember that 2nd row elements cannot form more than 4 bonds or have more than 8 electrons (octet rule).

2007-11-06 02:44:16 · answer #1 · answered by Nethicus 2 · 1 0

i think of this might nicely be a badly worded question. in case you had all those bonds, we might have six bonds to N. hence i think of what became into meant became into the two 2 sigmas and one pi, or 2 pi's which might contain 2 sigmas as portion of the pi as you suggested. In the two case, we might have 4 bonds to the nitrogen. Now which hybridization has 4 bonds? sp has 2 (combination one s and one p), sp2 has 3, sp3 has 4, BINGO, shall we bypass on nonetheless dsp3 has 5 and d2sp3 has 6.

2017-01-05 00:42:53 · answer #2 · answered by Anonymous · 0 0

No . Yhe valence of nitrogen is three. So not possible

2007-11-06 02:44:17 · answer #3 · answered by maussy 7 · 0 0

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