I really dont get this question....can someone please help me step by step?
Q: Ethylene glycol CH2(OH)CH2(OH) is common automobile antifreeze. It is soluble in water and fairly nonvolatile. Calculate the freezing point of a solution containing 651gram of ethylene glycol in 2505gram of water? (molar mass of ethylene glycol is 62.01gram/mole)
A:? help me.
2007-11-06 01:58:22 · 1 answers · asked by Kennedy 1 in Science & Mathematics ➔ Other - Science
Also...what temperature will the solution boil at?
2007-11-06 01:59:04 · update #1
The normal freezing point of water is 0C, and its Cryoscopic constant Kf = 1.86 K·kg/mol.
Molar mass of ethylene glycol is 62.07g/mole or 62.1g/mole (different from yours!). Hence 651gram of ethylene glycol is 10.49 mole
10.49 mole/2505g <==> 4.187m
Thus the freezing point of this solution is:
- (1.86 C·kg/mol)*(4.187m) = -7.79C
2007-11-07 12:54:54 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋