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Dear Yahoo Answers,

I need some help with the following Question.

Ammonium carbonate decomposes according to the equation below;

(NH^4)^2CO^3 = CO^2 + H^2O + 2NH^3

If 32 grams of (NH^4)^2CO^3 decomposes calculate;
Atomic weights to use: N = 14, H = 1.0, C = 12, O = 16
a. the mass of NH^3 gas produced

b. the volume of CO^2 produced if measured at STP?



Any contibution will be appreciated.

Thankyou

2007-11-06 01:29:44 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Atomic weights: N=14 H=1 C=12 O=16 (NH4)2CO3=96 NH3=18

Let ammonium carbonate be called AC

a. 32gAC x 1molAC/96gAC x 2molNH3/1molAC x 18gNH3/1molNH3 = 12g NH3

b. 32gAC x 1molAC/96gAC x 1molCO2/1molAC x 22.4LCO2/1molCO2 = 7.5L CO2

2007-11-06 01:39:07 · answer #1 · answered by steve_geo1 7 · 0 0

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