Here is a problem I need to figure out for extra credit in school. If I get the answer before all of the answers come in, I will delete this. Here it is!
Two cars depart from the same spot for the same destination. One travels at 60 mph, the other at 65 mpm. The faster car arrives at the destination one hour before the other one. How far (how many miles) was the destination from their departure point?
Good Luck!
2007-11-06 00:33:36 · 5 answers · asked by violinallegro1996 2 in Education & Reference ➔ Homework Help
Distance = speed x time
Set up the equation so that you can solve for d.
d = s x t
Let the time taken for the first car be t hours.
The second takes (t-1) hours.
So, here is the equation:
60 t = 65(t-1)
5 t = 65
t = 13 hours.
Now multiply the time by speed to get distance.
60 x 13 = 780 miles.
So, the distance form departure point to destination is 780 miles.
:)
2007-11-06 00:44:27 · answer #1 · answered by Emeralds 2 · 0⤊ 1⤋
656
2007-11-06 00:41:45 · answer #2 · answered by tinyfl27 4 · 1⤊ 1⤋
65-60=5mph difference.
60 miles is one hour different to slower driver.
60/5=15
65*15=975 miles
2007-11-06 00:43:04 · answer #3 · answered by Anonymous · 0⤊ 2⤋
x/60=x/65+1
65x=60x+3900
5x=3900
x=780 miles
2007-11-06 00:42:14 · answer #4 · answered by blizebliz 5 · 0⤊ 1⤋
i sure am glad im not in school anymore i hated those problems the most.
2007-11-06 00:38:04 · answer #5 · answered by Anonymous · 1⤊ 1⤋