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Find the derivative of

f (x) = sin 3x^2 / (3x+1)^2


thanks in advance for ur help

2007-11-05 18:46:30 · 2 answers · asked by Dr Virus 3 in Science & Mathematics Mathematics

2 answers

Hope you like your chain rule...

f'(x) = [(cos 3x^2) (6x) (3x+1)^2 - (sin 3x^2) (2) (3x+1) (3)] / (3x+1)^4
= [6x (3x+1) cos 3x^2 - 6 sin 3x^2] / (3x+1)^3

2007-11-05 18:58:18 · answer #1 · answered by Scarlet Manuka 7 · 0 0

If f(x) = g(x) / h(x)

then f'(x) = [g'(x) h(x) - g(x) h'(x)] / h^2 (x)

2007-11-05 18:56:41 · answer #2 · answered by j_kkachi 2 · 0 0

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