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In a football game, a tackle running at a constant speed of 6 m/s tackles a stationary receiver. The two fly off horizontally at 3 m/s. If the mass of the tackle is 145 kg,

a.) What is the mass of the receiver?

b.) Calculate the kinetic energy of the tackle-receiver system before and after the collision.
KEsys, i =
KEsys, f =

2007-11-05 18:19:04 · 2 answers · asked by =P 6 in Science & Mathematics Physics

2 answers

a)
3(m + 145) = (145)(6)
m + 145 = (145)(2)
m = 145 kg
b)
KEsys, i = (1/2)(145)6^2 = 2,610 J
KEsys, f = (1/2)(2*145)3^2 = 1,305 J

2007-11-05 18:51:13 · answer #1 · answered by Helmut 7 · 0 0

6*145 = 3* ( mr+ 145 ) → mr =241.67

K i = 1/2 mv^2 = 0.5*145*(6^2) =2610

K f = 1/2 ( 145+ 241.67 ) *3 ^2 = 1740

2007-11-05 18:41:41 · answer #2 · answered by Freddie 2 · 0 0

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