resistance sum???? please help me out?

Question

/\
/...\
/ \
the figure is in the form of the letter A the gaps and the dotted line in the middle represent the resistors there are totally 5 of them each of resistance 3 ohm
find the resistance between th points x and y
and explain how u did it

/\
/…\
x / \y

Answer 1

the answer is 8 ohm
2 pairs of resistors are in series so it will be 6ohm;3ohm,6ohm
they are all in parallel calculating them u get 8 ohms

Answer 2

i cant make diagram but i can make this clear with my best

see there are two resistance parallel to the middle resisitor

i.e. 6 ohm is paralel to a 3 ohm resisitor in the middle

solving this we get 1/Rp=1/6+1/3=1/2
i.e.Rp=2

now this Rp is in series with the other two 3 ohm resistance
solving this we get
Req=3+Rp+3=3+2+3=8 ohm which is the answer

Answer 3

R = r1 + r2(r3 + r4)/(r2 + (r3 + r4)) + r5
R = 3 + 3(3 + 3)/(3 + 3 + 3) + 3
R = 6 + 3(6)/(9)
R = 8