a crate and its load have a combined mass of 1600 kg. what is the tension in the supporting cable when the crate, originally moving downward at 12 m/s, is brought to rest with constant acceleration in a distance of 42 m.
please show how to solve and also answer
2007-11-05 17:40:01 · 2 answers · asked by magna1211@sbcglobal.net 1 in Science & Mathematics ➔ Physics
Initial downward velocity = 12 m/s
Final velocity = 0 m/s
Distance travelled= 42 m
Acceleration = ?
v² - u² = 2 a s
0² - (12)² = 2 a (42)
- 144 = 84 a
a = -144 / 84= -1.714 m/s²
In addition to this an additional opp. force is required to neutralise the acceleration due to gravity, 9.8 m/s²
Tension = m x a = 1600 x {(-1.714) +( -9.8)}= 18422.4 N upwards
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2007-11-05 18:35:03 · answer #1 · answered by Joymash 6 · 0⤊ 0⤋
a = (v^2 - v0^2)/(2s)
a = 144/84 = 12/7 upwards
T = m(a + g)
T = 1600(12/7 + 9.80665)
T â 18,433.50 N
2007-11-06 02:34:15 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋