Confusing Math Problem?

Question

BEADX4 = DAEB
A=?
B=?
D=?
E=?
This is a Math problem that puzzles me can you tell the answer to me and explain it? Please

Thank you in advance

BEAD times 4 = DAEB
just to be more specific

Answer 1

If this is for decoding:

BEAD x 4 = DAEB

4B4E4A4D = 1D1A1E1B

4B = 1D
4E = 1A
4A = 1E
4D = 1B

A = 4E
B = 4D
D = 4B
E = 4A

That's what I would think, tho the results are confusing.


If ABDE are variables though, by the multiplicative rule

B*E*A*D is the same thing as D*A*E*B.
In which case, to make BEAD * 4 = DAEB, at least one of them has to equal 0 (A,B,D, or E), and the rest can be any number.

I'd ask your math teacher to clarify this problem

Answer 2

It makes no sense. Because for example 4 times 2 = 2 times 4

so BEAD = DAEB , unles the X is also a variable, and not times, in that case X=1/4

Answer 3

If 210 are kinfolk and family members of the two the bride and groom, i'd subtract that 210 from 330, which provides a hundred and twenty. that's the variety of visitors left to ask who're no longer related to the two. i'd then divide the a hundred and twenty by way of 2, and that i'd say that each could invite 60. yet another probability is that via fact 210 human beings would be seen invitees of the two the bride and the groom, you will upload 210 to the 60, giving the two area 270 visitors (such as people who're receiving invites from the two the bride and the groom.) the problem isn't worded ok, and that i think of that's made to trick you. i think of my 2nd paragraph is the answer to the trick. If there is not any trick meant, it nevertheless isn't properly-written, yet then 60 often is the respond. pass arranged with the two solutions.

Answer 4

the only thing i can think of is either A,B,D,E is equal to A/4, then The 4 cancel each other.

Answer 5

A=A/4
B=B/4
E=E/4
D=D/4

simply cross multiply and cancel the common in numerator and denominator and you will get these answers.

Answer 6

how bout all of them equal 0