Find dy/dx for y= 4sin^2 (3x) please help n explain if u can appreciate it?

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please help

2007-11-05 14:55:58 · 2 answers · asked by omr 1 in Education & Reference ➔ Homework Help

It's simple chain rule calcuation dy/dx = 2 * 4sin 3x * d( sin 3x) /dx = 8sin 3x * 3 cos 3x = 24 sin 3x *cos3x

XR

2007-11-05 15:17:14 · answer #1 · answered by XReader 5 · 0⤊ 0⤋

let u = sin 3x
du/dx = 3 cos 3x
y = 4u^2
dy/du = 8u
dy/dx = dy/du * du/dx = 8u (3 cos 3x)

= 8 (sin 3x)(3 cos 3x)
= 24 sin 3x cos 3x

2007-11-05 23:01:39 · answer #2 · answered by hayharbr 7 · 0⤊ 1⤋