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how do you determine the mass of a star that IS part of a binary system?

2007-11-05 14:23:37 · 4 answers · asked by Anonymous in Science & Mathematics Astronomy & Space

4 answers

Its based on the orbital period of the two objects and their distances from each other.
The regular wobble of each star's motion gives the period, the apparent separation of the stars gives their distance from each other.

2007-11-05 14:56:26 · answer #1 · answered by Anonymous · 0 0

You also need to know its distance so you can estimate the diameter, as well as the period , of its orbit. From that, simple orbital mechanics can tell you the mass of the binary's component stars.

2007-11-05 14:56:43 · answer #2 · answered by injanier 7 · 0 0

Measuring the changes in their orbits as they pass one another

2007-11-05 14:27:52 · answer #3 · answered by Thomas F 1 · 0 0

? for this reason m1*r1=m2*r2 is equation for their mass middle, the place r1 is radius of rotation of seen m1, r2 is radius of rotation of invisible m2, radii being measured from their common mass middle – the beginning of the gadget; for this reason r2=r1*(m1/m2); ? additionally circumference of orbit of m1 is 2pi*r1=v1*T, for this reason r1=v1*T/2pi; ? the strain of their mutual gravitation F=G*m1*m2/(r1+r2)^2 is likewise their mutual centripetal tension F= m1*v1^2/r1; for this reason G*m2/(r1+r2)^2=v1^2/r1; or; G*m2= (v1^2/r1)*(r1+r2)^2; plugging r2 of (?) we get G*m2= v1^2*r1 *(a million+m1/m2)^2; plugging r1 of (?) we get G*m2= v1^2* (v1*T/2pi) *(a million+m1/m2)^2; or; m2^3=v1^3*T/(2pi*G) *(m2+m1)^2; or; m^3= v1^3*T/(2pi*G*m1) *(m+a million)^2, the place m=m2/m1, G= 6.6742x10^-11, v1=0.270·10^6 m/s, T=a million.7*24*3600s, m1=6* 6*a million.ninety 9·10^30 kg; ? m^3=0.096232* (m+a million)^2, for this reason m=0.6364, m2= 3.8184 Suns; now Rajjy, take your arms out of your wallet and consider me!

2016-12-08 13:18:37 · answer #4 · answered by ? 4 · 0 0

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