Find the intercepts of the function?

Question

I can find the asymptotes no problem, but having trouble with the intercepts
G(x)= (x+2) / x^2+2x-3
G(x)= (x^2-3x-7) / (x+3)

Answer 1

The y-intercept is found by making x = 0 and solve for y.
The x-intercept is found by making y = 0 (or G(x) = 0) and solving for x.

1)

G(x) = (x + 2) / (x^2 + 2x - 3)

First, the y-intercept; make x = 0.

G(0) = (0 + 2) / (0^2 + 2*0 - 3)
G(0) = 2/(0 + 0 - 3)
G(0) = 2/(-3)
G(0) = -2/3

Therefore, the y-intercept is -2/3.

To find the x-intercepts, make G(x) = 0.

0 = (x + 2) / (x^2 + 2x - 3)

This is only true if the numerator is 0; that is, if
(x + 2) = 0, or
x = -2

Therefore, the x-intercept is -2.

Solve #2 on your own using the same concept.

Answer 2

Why are you posting the same question again. You have three answers from the last time.

Answer 3

WTF
sorry man