A force problem?

Question

A 873-kg (1930-lb) dragster, starting from rest, attains a speed of 26.3 m/s (58.9 mph) in 0.59s.

My teacher is only making us do book work and i'm really stressing because i don't know how to dso this, we're barely learning about forces.... help and thankyou

Answer 1

F=m dV/dt
or
F= m (v2-V1)/(t2-t1) this is not instantaneous but an average acceleration

F= 873 (26.3- 0)/(0.59 -0)= 38,900 N

If the wheel of the dragster is 1.2m then the torque id
T=rxF= (1.2/ 2) 38900= 23,340 mN

Answer 2

So what is the question to this problem?

~pinoyplaya