Physics - Distance.?

Question

A car starting from rest moves with constant acceleration of 3.1 m/s^2 for 13 s, then travels with constant speed for another 19 s, and then finally slows to a stop with constant acceleration of -8.5 m/s^2. How far does it travel in meters?

Steps please. Thanks =)

Answer 1

First part
d1=.5*3.1*13^2
262 m
vi=3.1*13
40.3 m/s
Second part
d2=3.1*13*19
766 m
Third part
0=3.1*13-8.5*t3
solve for t3 and use
d3=3.1*13*t3-.5*8.5*t3^2

t3=4.74 seconds
d3=95.5 m

Total distance is
1123.5 m

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