Calculating molarity of 2 solutions?

Question

Calculate the molarity of a solution of NaOH if 34.22mL of this base reacts completely with 48.52mL of 0.1245M (molarity) HNO3 (aq)?

Please help, im stuck!

Answer 1

Principles:

Amount = concentration x volume

mmol H+ used = mmol OH- neutralized.

You used 48.52 mL of 0.1245 mole/L HNO3.

That was 48.52 x 0.1245 mmol HNO3

One NaOH reacts with one HNO3. So you had the same number of mmol of NaOH.

Now you know how much NaOH you had, you can write

molarity of NaOH (unknown) x 34.22 mL = [number of mmol that you just calculated]

Rearrange to make your unknown the only subject, and punch the numbers into your calculator.