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Find the Least Common Multiple (LCM)

3, 7, and 10

6, 7, and 8

2007-11-05 11:24:32 · 6 answers · asked by awesomeqt53 3 in Science & Mathematics Mathematics

6 answers

Do these 2 at a time.
Use the fact that the LCM of a and b equals
a*b/GCD(a,b).
So LCM(3,7) = 21
LCM(21,10) = 210
The answer to the first one is 210
Second one
LCM(6,7) = 42
LCM(42,8) = 42*8/2 = 168.

2007-11-05 11:39:10 · answer #1 · answered by steiner1745 7 · 0 0

LCM(3, 7, 10) = 210

LCM(6, 7, 8) = 168

2007-11-05 19:28:49 · answer #2 · answered by A A 3 · 2 0

210
24

2007-11-05 19:28:26 · answer #3 · answered by GolfinUnderPar 2 · 0 2

a) 210

b) 168

2007-11-05 19:30:57 · answer #4 · answered by George23 3 · 0 0

210

168

2007-11-05 19:29:22 · answer #5 · answered by ET 2 · 0 1

210
24

2007-11-05 19:27:42 · answer #6 · answered by golferp387 1 · 0 2

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