How do I determine the oxidation states for atoms that contain more than two elements? For example:
-Na4Fe(OH)6
-XeOF4
-C6H12O6
I don't know how to figure out the individual oxidation states. Can anyone help me? Please?
2007-11-05 08:48:59 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
some elements have only one oxidation state, but others can have more than one.
sodium and oxygen are always 1+ and 2- , respectively
H is always 1+
therefore
4Na(1+) + 6 OH(1-) = 2-
the compound always has net zero charge and Fe must be 2+
Fe(II) ferrous
F is always 1- so Xe is 6+
C6H12O6 is a covalent molecule (sugar)
2007-11-05 08:55:34 · answer #1 · answered by ferrous lad 4 · 0⤊ 0⤋
Na4 is the positive redical in which each Na has o.s of +1 and total charge is +4
Fe(OH)6 is the negative redical in which each OH has o.s of -1 so total charge is -6
as to balance the charge of the positive redical the negative redical should have a total charge of -4 so Fe has o.s of +2
2007-11-05 09:02:20 · answer #2 · answered by ronaq 2 · 0⤊ 0⤋
1. Fe = 4
2. O = -2 F=-1, so Xe=+6 (gotta be!)
3. C=0 (gotta be!)
2007-11-05 08:57:16 · answer #3 · answered by steve_geo1 7 · 0⤊ 0⤋
don't know. but if jeff gordon does not start racing better he is going down to jimmie
2007-11-07 09:59:22 · answer #4 · answered by Joe 3 · 0⤊ 0⤋