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jims second test score was 8 points higher than his first test score. his third score was 88. he a b average (between 80-89 inclusive)for the three tests.

2007-11-05 07:22:45 · 1 answers · asked by clcsexyma1 1 in Science & Mathematics Mathematics

1 answers

b = a + 8
c = 88

80 <= (a + a+8 + 88)/3 <= 89
80 <= (2a + 96)/3 <= 89
240 <= 2a + 96 <= 267
144 <= 2a <= 171
72 <= a <= 85.5 (first test possible scores)
80 <= a <= 93.5 (second test possible scores)

2007-11-05 07:30:37 · answer #1 · answered by gebobs 6 · 0 0

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