Its to do with rational exponents.
2007-11-05 05:54:49 · 4 answers · asked by marcus33 1 in Science & Mathematics ➔ Mathematics
64^(-4/3) = (2^6)^(-4/3) or 64^(-4/3) = (4^3)^(-4/3)
Since (a^b)^c = a^(b•c),
64^(-4/3) = 2^[6•(-4/3)] or 64^(-4/3) = 4^[3•(-4/3)]
Simplify the exponent terms.
64^(-4/3) = 2^(-8) or 64^(-4/3) = 4^(-4)
Since a^(-b) = 1/(a^b),
64^(-4/3) = 1/(2^8) or 64^(-4/3) = 1/(4^4)
64^(-4/3) = 1/256
2007-11-05 06:07:58 · answer #1 · answered by richarduie 6 · 0⤊ 0⤋
64 to the power -4/3= 1/ (64)^4/3.= 1/ (8)^2^4/3= 1/ 8^8/3.
Ans. 1/8 ^8/3.
64- 4/3= 188/3= 62.66
2007-11-05 06:27:49 · answer #2 · answered by Sasi Kumar 4 · 0⤊ 0⤋
64 -4/3 = 3rd root of 64=4 4^-4= 4 ^1/4 4th root =1/256
2007-11-05 06:46:00 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Using calculator:
64^( -4/3) = .00390625 approximation decimal
2007-11-05 06:02:15 · answer #4 · answered by gzlakewood@sbcglobal.net 4 · 0⤊ 0⤋