How would I solve : 3^x - 6 = 7?

1 ⤊

Okay, I know you solve for x, but that would leave me with log 3 (13) and I don't think that's correct. Please let me know what you think. Thanks.

2007-11-05 05:33:33 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3^x = 13
x log 3 = log 13
x = log 13 / log 3

2007-11-05 05:39:26 · answer #1 · answered by Como 7 · 0⤊ 0⤋

como seems pretty smart to me, then you just plug in the logs and find the values. Teachers might mark you wrong if you leave it in that form.

2007-11-05 13:43:25 · answer #2 · answered by kylerocks7 1 · 0⤊ 0⤋

Wouldn't it be log13/log3? take the log of both sides, move the x to the outside of log3...

2007-11-05 13:37:18 · answer #3 · answered by Chelsea 2 · 1⤊ 0⤋